document.write( "Question 1032035: Spartanland has a stand that sells souvenir hats. Last year the stand charged $5 each, and they sold 150. they want to increase the price this year, and they expect to lose 10 sales for each $1 increase. The sales revenue, R, in dollars, generated by selling the hats is predicted by the function: R = (5 + p) (150 - 10p), where p is the price increase in dollars \n" ); document.write( "
Algebra.Com's Answer #646733 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Spartanland has a stand that sells souvenir hats. Last year the stand charged $5 each, and they sold 150. they want to increase the price this year, and they expect to lose 10 sales for each $1 increase. The sales revenue, R, in dollars, generated by selling the hats is predicted by the function: R = (5 + p) (150 - 10p), where p is the price increase in dollars \n" ); document.write( "------- \n" ); document.write( "The usual question on this type of problem is to maximize Revenue. \n" ); document.write( "--------------------- \n" ); document.write( "R = 5*150 -50p + 150p - 10p^2 \n" ); document.write( "--- \n" ); document.write( "R = -10p^2 + 100p + 750 \n" ); document.write( "------ \n" ); document.write( "Maximum R occurs when p = -b/(2a) = -100/(2*-10) = 5 \n" ); document.write( "--------------------------- \n" ); document.write( "To maximize revenue increase the price by $5 \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " \n" ); document.write( " |