document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88975>Question 88975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50.  \r<BR>\n" );
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document.write( "Part A: Setup an equationfor the perimeter involving only L, the length of the rectangle.\r<BR>\n" );
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document.write( "Part B: Solve this equation algebraically to find the length of the rectangle. Find the width as well.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64673 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=L-5<BR>\n" );
document.write( "2W+2L=50<BR>\n" );
document.write( "2(L-5)+2L=50<BR>\n" );
document.write( "2L-10+2L=50<BR>\n" );
document.write( "4L-10=50<BR>\n" );
document.write( "4L=50+10<BR>\n" );
document.write( "4L=60<BR>\n" );
document.write( "L=60/4<BR>\n" );
document.write( "L=15 ANSWER FOR THE LENGTH.<BR>\n" );
document.write( "W=15-5<BR>\n" );
document.write( "W=10 ANSWER FOR THE WIDTH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*10+2*15=50<BR>\n" );
document.write( "20+30=50<BR>\n" );
document.write( "50=50\r<BR>\n" );
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document.write( " </SPAN>\n" );
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