document.write( "Question 1032019: The mean and standard deviation of 500 students who took a statistics final were 72 and 8, respectively. The grades have a mound-shape distribution. Based upon this information, the best estimate of the percentage of students who scored higher than 80 on the exam is \r
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document.write( "A 68%
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document.write( "B 32%
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document.write( "C 16%
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document.write( "D 5%
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document.write( "E 2.5% \n" );
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Algebra.Com's Answer #646723 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The mean and standard deviation of 500 students who took a statistics final were 72 and 8, respectively. The grades have a mound-shape distribution. Based upon this information, the best estimate of the percentage of students who scored higher than 80 on the exam is \n" ); document.write( "------ \n" ); document.write( "(80-72)/8 = 1 \n" ); document.write( "That means a score of 80 is one standard deviation above the mean> \n" ); document.write( "------------------- \n" ); document.write( "Since 68% of the data is within 1 standard deviation of the mean, \n" ); document.write( "34% is within 1 std to the right of the mean. \n" ); document.write( "So 50% - 34% = 16% of the scores are higher than 80 \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( "A 68% \n" ); document.write( "B 32% \n" ); document.write( "C 16% \n" ); document.write( "D 5% \n" ); document.write( "E 2.5% \n" ); document.write( " |