document.write( "Question 1032019: The mean and standard deviation of 500 students who took a statistics final were 72 and 8, respectively. The grades have a mound-shape distribution. Based upon this information, the best estimate of the percentage of students who scored higher than 80 on the exam is \r
\n" ); document.write( "\n" ); document.write( "A 68%
\n" ); document.write( "B 32%
\n" ); document.write( "C 16%
\n" ); document.write( "D 5%
\n" ); document.write( "E 2.5%
\n" ); document.write( "

Algebra.Com's Answer #646723 by stanbon(75887)\"\" \"About 
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The mean and standard deviation of 500 students who took a statistics final were 72 and 8, respectively. The grades have a mound-shape distribution. Based upon this information, the best estimate of the percentage of students who scored higher than 80 on the exam is
\n" ); document.write( "------
\n" ); document.write( "(80-72)/8 = 1
\n" ); document.write( "That means a score of 80 is one standard deviation above the mean>
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\n" ); document.write( "Since 68% of the data is within 1 standard deviation of the mean,
\n" ); document.write( "34% is within 1 std to the right of the mean.
\n" ); document.write( "So 50% - 34% = 16% of the scores are higher than 80
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "--------------
\n" ); document.write( "A 68%
\n" ); document.write( "B 32%
\n" ); document.write( "C 16%
\n" ); document.write( "D 5%
\n" ); document.write( "E 2.5%
\n" ); document.write( "
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