document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032022>Question 1032022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm so close to solving this question but any input would be so greatly appreciated! I'm having trouble coming up with the right 3 equations for this problem:\r<BR>\n" );
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document.write( "\"The sum of three numbers is 14. The first number minus three times the third number is the second number. The second number is six more than the first number. Find the three numbers.\"\r<BR>\n" );
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document.write( "Thank you for any input. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646707 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y+z=14<BR>\n" );
document.write( "x-3z=y<BR>\n" );
document.write( "y=x+6<BR>\n" );
document.write( "x-3z=x+6<BR>\n" );
document.write( "-3z=6<BR>\n" );
document.write( "z=-2<BR>\n" );
document.write( "x+y=16, going back to the first equation.<BR>\n" );
document.write( "y=x+6<BR>\n" );
document.write( "so x+x+6=16<BR>\n" );
document.write( "2x=10<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( "y=11<BR>\n" );
document.write( "The numbers are 5, 11, -2<BR>\n" );
document.write( "They add to 14 <BR>\n" );
document.write( "The first number minus 3 (-2)= 11<BR>\n" );
document.write( "The second number is 6 more than the first.<BR>\n" );
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