document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032013>Question 1032013</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (cosx-secx)/secx = -sin^2x<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646706 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin^2x=1-cos^2x<BR>\n" );
document.write( "-sin^2x=cos^2x-1<BR>\n" );
document.write( "(cosx-secx)/secx = -sin^2x<BR>\n" );
document.write( "rewrite left side as<BR>\n" );
document.write( "cosx/secx -1<BR>\n" );
document.write( "but that is cos x/(1/cos x)=cos^2x<BR>\n" );
document.write( "Therefore, the left side is cos^2x-1 which is -sin^2x </SPAN>\n" );
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