document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032009>Question 1032009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy is twice as old has his sister and half as old as his father in 50 years she will be twice as old as her father how old is the boy now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646701 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sister is x years<BR>\n" );
document.write( "boy is 2x<BR>\n" );
document.write( "father is 4x<BR>\n" );
document.write( "x+50=8x, twice as old as her father is now (I have to assume that).<BR>\n" );
document.write( "7x=50<BR>\n" );
document.write( "x=(50/7)<BR>\n" );
document.write( "boy is 100/7 years old (14 2/7) years<BR>\n" );
document.write( "father is 200/7 years old (28 4/7)<BR>\n" );
document.write( "in 50 years, the 7 (1/7) year old girl will be 57 (1/7) years, and that is twice as much as her 28 (4/7) year old father, who has a son 14 2/7 year old. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );