document.write( "Question 1032005: A (n)=0.5*3^n-1. I need to find the first fourth and eighth term. If you explain in simplest terms I would be super greatful \n" ); document.write( "

Algebra.Com's Answer #646694 by Boreal(15235) $\"\"$ $\"About$

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A (n)=0.5*3^(n-1); I am assuming n-1 is the exponent.
\n" ); document.write( "I would substitute the number for n
\n" ); document.write( "A(1)=0.5*3^(1-1)=0.5*3^0; 3^0=1, so A(1)=0.5
\n" ); document.write( "A(4)=0.5*3^(4-1)=0.5*3^3; 3^3=27, and 27*(0.5)=13.5
\n" ); document.write( "A(8)=0.5*3^(8-1)=0.5*3^7;3^7=2187. and 2187*0.5=1093.5 \n" ); document.write( "

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