document.write( "Question 1031950: The time that customers take to complete their transaction at a money machine is a random variable with mean of 2 minutes and a standard deviation of 0.6 minutes. Assume the variable is normally distributed.\r
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document.write( "a) What is the probability that a randomly selected customer will take between 1.5 and 2.5 minutes to complete his transaction?
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document.write( "b) Find the probability that a random sample of 50 customers will take more than 112 minutes to complete all their transactions
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Algebra.Com's Answer #646663 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The time that customers take to complete their transaction at a money machine is a random variable with mean of 2 minutes and a standard deviation of 0.6 minutes. Assume the variable is normally distributed. \n" ); document.write( "a) What is the probability that a randomly selected customer will take between 1.5 and 2.5 minutes to complete his transaction? \n" ); document.write( "--- \n" ); document.write( "z(1.5) = (1.5-2)/0.6 = -0.8333 \n" ); document.write( "z(2.5) = (2.5-1.5)/0.6 = 1/0.6 = 10/6 = 5/3 \n" ); document.write( "--- \n" ); document.write( "P(1.5< x < 2.5) = P(-0.8333< z < 5/3) = normalcdf(-0.8333,5/3) = 0.7500 \n" ); document.write( "============================= \n" ); document.write( "b) Find the probability that a random sample of 50 customers will take more than 112 minutes to complete all their transactions \n" ); document.write( "z(112) = (112-2)/(0.6/sqrt(50)) = 1296 \n" ); document.write( "--- \n" ); document.write( "Note:: I suspect there is a typo in your post. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------- \n" ); document.write( " |