document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031941>Question 1031941</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Gilda walks to the train station. If she walks at the rate of 3 mph, she misses her train by 7 minutes. However, if she walks at the rate of 4 mph, she reaches the station 5 minutes before the arrival of the train. Find the distance Gilda walks to the station.  David knew he made a mistake when he calculated that Gilda walks 123 miles to the station. <BR>\n" );
document.write( "Read through David's calculations:<BR>\n" );
document.write( "Using d = rt, the distance is the same, but the rate and time are different.<BR>\n" );
document.write( "If Gilda misses the train, it means the time t needs 7 more minutes so d = 3(t + 7).<BR>\n" );
document.write( "If she gets to the station 5 minutes early means the time t can be 5 minutes less so d = 4(t - 5).<BR>\n" );
document.write( "3(t + 7) = 4(t - 5)<BR>\n" );
document.write( "3t + 21 = 4t - 20<BR>\n" );
document.write( "t = 41<BR>\n" );
document.write( "d = rt, so d = 3(41) = 123<BR>\n" );
document.write( "Find David's mistake in his calculations. Explain his mistake and include the correct calculations and solutions in your answer.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646645 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646645\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Gilda walks to the train station. If she walks at the rate of 3 mph, she misses her train by 7 minutes. However, if she walks at the rate of 4 mph, she reaches the station 5 minutes before the arrival of the train. Find the distance Gilda walks to the station.  David knew he made a mistake when he calculated that Gilda walks 123 miles to the station. <BR>\n" );
document.write( "Read through David's calculations:<BR>\n" );
document.write( "Using d = rt, the distance is the same, but the rate and time are different.<BR>\n" );
document.write( "If Gilda misses the train, it means the time t needs 7 more minutes so d = 3(t + 7).<BR>\n" );
document.write( "If she gets to the station 5 minutes early means the time t can be 5 minutes less so d = 4(t - 5).<BR>\n" );
document.write( "3(t + 7) = 4(t - 5)<BR>\n" );
document.write( "3t + 21 = 4t - 20<BR>\n" );
document.write( "t = 41<BR>\n" );
document.write( "d = rt, so d = 3(41) = 123<BR>\n" );
document.write( "Find David's mistake in his calculations. Explain his mistake and include the correct calculations and solutions in your answer.\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( "DUPLICATE PROBLEM. See # 1029838<BR>\n" );
document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">I worked it out then and I did get distance to be: 2.4 km also.<BR>\n" );
document.write( "Why do some of you keep reposting problems that have already been answered? Are the solutions not enough? <BR>\n" );
document.write( "By the way, itw's TOTALLY UNNECESSARY for David to calculate time. Time is not being sought, and so, should be EXCLUDED from the solution. <BR>\n" );
document.write( "A TIME equation should be formed though. </SPAN>\n" );
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