document.write( "Question 1031958: He all, Can somebody explain me the reason why for this equation:\r
\n" ); document.write( "\n" ); document.write( "tan(10° - 4x) = -1/3^(1/2)\r
\n" ); document.write( "\n" ); document.write( "the proposed solution is x=10°-k45° and not x=10°-k180°\r
\n" ); document.write( "\n" ); document.write( "This brings to the following 8 results in the first round of 360°:
\n" ); document.write( "10°, 55°, 100°, 145°, 190°, 235°, 280°, 325°
\n" ); document.write( "What causes this coeff k45° to be applied?
\n" ); document.write( "Thank you very much and regards
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Algebra.Com's Answer #646631 by ikleyn(52879)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "He all, Can somebody explain me the reason why for this equation:\r
\n" ); document.write( "\n" ); document.write( "tan(10° - 4x) = -1/sqrt(3)\r
\n" ); document.write( "\n" ); document.write( "the proposed solution is x=10°-k45° and not x=10°-k180°\r
\n" ); document.write( "\n" ); document.write( "This brings to the following 8 results in the first round of 360°:
\n" ); document.write( "10°, 55°, 100°, 145°, 190°, 235°, 280°, 325°
\n" ); document.write( "What causes this coeff k45° to be applied?
\n" ); document.write( "Thank you very much and regards
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document.write( "tan(10° - 4x) = \"-1%2Fsqrt%283%29\"   --->\r\n" );
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document.write( "10° - 4x = -30° + k*180°         (I wrote \" + k*180° \", since 180° is the period of the tangent function).\r\n" );
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document.write( "From this equation we have \r\n" );
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document.write( "4x = 40°  - k*180°,  k = 0, +/-1, +/-2, . . . \r\n" );
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document.write( "and hence\r\n" );
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document.write( "x = 10° - k*45°,  k = 0, +/-1, +/-2, . . . \r\n" );
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