document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88957>Question 88957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My teacher says what I am doing is wrong please help me with these to.\r<BR>\n" );
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document.write( "For each equation in exercises 26 and 28, identify the axis of symmetry, create a suitable<BR>\n" );
document.write( "table of values, and sketch the graph (including the axis of symmetry).\r<BR>\n" );
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document.write( "26. x^2-5x+3\r<BR>\n" );
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document.write( "28. x^2+6x-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64663 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for a quadratic of the form ax^2+bx+c, the equation for the axis of symmetry is x=-b/(2a) ... once you find this value, you should select values on either side of it for a \"suitable\" table of values ... the y values are found by plugging the x values into the quadratic\r<BR>\n" );
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document.write( "28.  x^2+6x-2 ... axis of symmetry, x=-6/(2*1), x=-3 ... table of values; (-3,-11), (-2,-10), (-4,-10), (0,-2), (-6,-2), (1,5), (-7,5) ... these are also the points for graphing\r<BR>\n" );
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document.write( "the axis of symmetry is a vertical line at x=-3 </SPAN>\n" );
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