document.write( "Question 88954: The sum of the digits of a three -digit number is 17. The ones degit is two more than the hundreds digit. The tens digit is one more than the hundreds digit. What is the number? \n" ); document.write( "

Algebra.Com's Answer #64662 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
RE-CHECK YOUR PROBLEM. SOMETHING'S WRONG (AND IT COULD BE ME BUT I DOUBT IT)\r
\n" ); document.write( "\n" ); document.write( "Let x=the hundreds digit
\n" ); document.write( "Then x+1=the tens digit
\n" ); document.write( "And x+2=the ones digit\r
\n" ); document.write( "\n" ); document.write( "Now we are told that:\r
\n" ); document.write( "\n" ); document.write( "x+x+1+x+2=17 collect like terms
\n" ); document.write( "3x+3=17 subtract 3 from both sides\r
\n" ); document.write( "\n" ); document.write( "3x+3-3=17-3 collect like terms\r
\n" ); document.write( "\n" ); document.write( "3x=14 divide both sides by 3\r
\n" ); document.write( "\n" ); document.write( "x=4.666667 ??????????????????????????\r
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\n" ); document.write( "\n" ); document.write( "Something's wrong. x should be a whole number.\r
\n" ); document.write( "\n" ); document.write( "If the sum was 18 instead of 17, then the problem has a solution (567)
\n" ); document.write( "x=5
\n" ); document.write( "x+1=6
\n" ); document.write( "x+2=7\r
\n" ); document.write( "\n" ); document.write( "5+6+7=18
\n" ); document.write( "18-18\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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