document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031906>Question 1031906</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"How far can an airplane fly from its base, and yet return within 3 hours, if its outgoing speed is 600 kilometers per hour and its returning speed is 400 kilometers per hour?\" Can you help me with this?? Thanks in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646584 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Convert to minutes:<BR>\n" );
document.write( " 3*60 = 180 minutes<BR>\n" );
document.write( " and 600/400 = 1.5 It takes 1.5 times longer coming back<BR>\n" );
document.write( " x+1.5x= 180<BR>\n" );
document.write( " 2.5x = 180<BR>\n" );
document.write( " x = 72 minutes is the fast speed<BR>\n" );
document.write( " and<BR>\n" );
document.write( " 72*1.5 = 108 is the fast speed<BR>\n" );
document.write( " 72+108=180 minutes and 180/60 = 3 hours of flight total.   </SPAN>\n" );
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