document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031863>Question 1031863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> frank went 16 miles at one speed and then caame back going 4mph faster. if the return trip took 40mins less time find the 2 speeds.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646565 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646565\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Forward time - return time = 40 minutes = 2/3 hours\r<BR>\n" );
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document.write( "Let forward rate be x<BR>\n" );
document.write( "return rate = x+4\r<BR>\n" );
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document.write( "16/x - 16/(x+4) = 2/3\r<BR>\n" );
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document.write( "LCD\r<BR>\n" );
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document.write( "3x(x+4)\r<BR>\n" );
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document.write( "48(x+4) -48x = 2*3x(x+4)\r<BR>\n" );
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document.write( "48x + 192 -48x = 6x^2+24x\r<BR>\n" );
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document.write( "6x^22 +24x -192=0\r<BR>\n" );
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document.write( "/6<BR>\n" );
document.write( "x^2+4x-32=0\r<BR>\n" );
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document.write( "x^2+8x-4x-32=0\r<BR>\n" );
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document.write( "x(x+8)-4(x+8) =0\r<BR>\n" );
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document.write( "(x+8)(x-4) =0\r<BR>\n" );
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document.write( "x=4 the positive value\r<BR>\n" );
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document.write( "4 mph & 8 mph </SPAN>\n" );
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