document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031873>Question 1031873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kathy is twice as old as Lisa. Three years from now, the sum of their ages will be 42. How old is Kathy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646560 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Kathy is twice as old as Lisa. Three years from now, the sum of their ages will be 42. How old is Kathy? <BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "K = 2L<BR>\n" );
document.write( "K+3 + L+3 = 42<BR>\n" );
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document.write( "Substitute for \"K\" and solve for \"L\":<BR>\n" );
document.write( "2L + 3 + L+3 = 42<BR>\n" );
document.write( "3L + 6 = 42<BR>\n" );
document.write( "L + 3 = 21<BR>\n" );
document.write( "Lisa = 18 yrs<BR>\n" );
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document.write( "Kathy = 2L = 36 yrs<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );