document.write( "Question 1031864: A metallurgist has one alloy containing 29% copper and another containing 53% copper. How many pounds of each alloy must he use to make 49 pounds of a third alloy containing 34% copper? (Round to two decimal places if necessary.) \n" ); document.write( "
Algebra.Com's Answer #646549 by mananth(16946)\"\" \"About 
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\n" ); document.write( "Copper
\n" ); document.write( " percent ---------------- quantity
\n" ); document.write( "Alloy I 29.00% ---------------- x lb
\n" ); document.write( "Alloy II 53.00% ------ 49 - x lb
\n" ); document.write( "Mixture 34.00% ---------------- 49
\n" ); document.write( " 49
\n" ); document.write( "29.00% x + 53.00% ( 49 - x ) = 34.00% * 49
\n" ); document.write( "29 x + 53 ( 49 - x ) = 1666
\n" ); document.write( "29 x + 2597 - 53 x = 1666
\n" ); document.write( "29 x - 53 x = 1666 - -2597
\n" ); document.write( "-24 x = -931
\n" ); document.write( "/ -24
\n" ); document.write( " x = 38.79 lb 29.00% Alloy I
\n" ); document.write( " 10.21 lb 53.00% Alloy II
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\n" ); document.write( "m.ananth@hotmail.ca
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