document.write( "Question 1031823: I need help with formulas and how to apply them to this type of question\r
\n" ); document.write( "\n" ); document.write( "The average age of Chief police is 56 years. Assume the variable is normally distributed. If the standard deviation is four years, find the probability that the age of a randomly selected Chief will be in the following range.
\n" ); document.write( " a. Between 53 and 59 years old
\n" ); document.write( " b. Between 58 and 63 years old
\n" ); document.write( " c. Between 50 and 55 years old
\n" ); document.write( "
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Algebra.Com's Answer #646535 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "TI syntax is normalcdf(smaller, larger, µ, σ).
\n" ); document.write( "Mean 56 SD = 4
\n" ); document.write( "a. Between 53 and 59 years old:
\n" ); document.write( "P(53 ≤ x ≤ 59)= normalcdf(53, 59, 56, 4)=.5467
\n" ); document.write( " b. Between 58 and 63 years old:
\n" ); document.write( "P(58 ≤ x ≤ 63)= normalcdf(59, 63, 56, 4) = .1857
\n" ); document.write( " c. Between 50 and 55 years old:
\n" ); document.write( "P(50 ≤ x ≤ 55)= normalcdf(50, 55, 56, 4) = .3345 \n" ); document.write( "
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