document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031850>Question 1031850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is 4 times old as his daughter was 3 years ago.If their combined ages is 48,how old is the daughter now?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646519 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the daughter's age be x now\r<BR>\n" );
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document.write( "3 years ago her age was (x-3) years\r<BR>\n" );
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document.write( "Father's age now is 4(x-3)\r<BR>\n" );
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document.write( "4(x-3)+48\r<BR>\n" );
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document.write( "4x-12=48<BR>\n" );
document.write( "4x=12+48<BR>\n" );
document.write( "4x=60<BR>\n" );
document.write( "x=15 years the daughter's age\r<BR>\n" );
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