document.write( "Question 1031806: Bob paddled against current for 2 hrs. and then with current for 1 hr. and rested. Rick paddled against current for 2.5 hrs. and then with current for 1.5 hrs. If they paddled a total of 9.5 miles against the current and 20.5 miles with the current and the current is 3 mph. How fast do they paddle in still water? \n" ); document.write( "
Algebra.Com's Answer #646490 by mananth(16946)\"\" \"About 
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Bob paddled against current for 2 hrs. and then with current for 1 hr. and rested.
\n" ); document.write( "let Bob's speed in still water be x
\n" ); document.write( "with current his speed will be x+3 mph
\n" ); document.write( "with current he paddled for (x+3) * 1\r
\n" ); document.write( "\n" ); document.write( "against current his speed will be x-3 mph
\n" ); document.write( "against current he paddled f or (x-3)*2\r
\n" ); document.write( "\n" ); document.write( "Rick with current for 1.5 hrs.
\n" ); document.write( " let Rick's speed in still water be y
\n" ); document.write( "with current his speed will be y+3 mph
\n" ); document.write( "with current he paddled for (y+3) * 1.5\r
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\n" ); document.write( "\n" ); document.write( "Rick paddled against current for 2.5 hrs. \r
\n" ); document.write( "\n" ); document.write( "against current his speed will be y-3 mph
\n" ); document.write( "against current he paddled f or (y-3)*2.5\r
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\n" ); document.write( "\n" ); document.write( "If they paddled a total of 9.5 miles against the current
\n" ); document.write( "(x-3)*2 +(y-3)*2.5 = 9.5
\n" ); document.write( "2x-6 +2.5y -7.5 =9.5
\n" ); document.write( "2x+2.5y = 23...........................(1)\r
\n" ); document.write( "\n" ); document.write( " and 20.5 miles with the current\r
\n" ); document.write( "\n" ); document.write( "(x+3) * 1+ (y+3) * 1.5=20.5\r
\n" ); document.write( "\n" ); document.write( "x+3 +1.5y +4.5 =20.5\r
\n" ); document.write( "\n" ); document.write( "x+1.5y=13.......................(2)\r
\n" ); document.write( "\n" ); document.write( "2.00 x + 2.50 y = 23.00 .............1
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\n" ); document.write( "1.00 x + 1.50 y = 13.00 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -1.50
\n" ); document.write( "Multiply (2) by 2.50
\n" ); document.write( "-3.00 x -3.75 y = -34.50
\n" ); document.write( "2.50 x + 3.75 y = 32.50
\n" ); document.write( "Add the two equations
\n" ); document.write( "-0.50 x = -2.00
\n" ); document.write( "/ -0.50
\n" ); document.write( "x = 4.00
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "2.00 x + 2.50 y = 23.00
\n" ); document.write( "8.00 + 2.50 y = 23.00
\n" ); document.write( " 2.50 y = 23.00 -8.00
\n" ); document.write( " 2.50 y = 15.00
\n" ); document.write( " y = 6.00
\n" ); document.write( "x= 4.00 mph Bob's speed
\n" ); document.write( "y= 6.00 mph Rick's speed \r
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\n" ); document.write( "m.ananth@hotmail.ca \r
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