document.write( "Question 1031806: Bob paddled against current for 2 hrs. and then with current for 1 hr. and rested. Rick paddled against current for 2.5 hrs. and then with current for 1.5 hrs. If they paddled a total of 9.5 miles against the current and 20.5 miles with the current and the current is 3 mph. How fast do they paddle in still water? \n" ); document.write( "
Algebra.Com's Answer #646490 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Bob paddled against current for 2 hrs. and then with current for 1 hr. and rested. \n" ); document.write( "let Bob's speed in still water be x \n" ); document.write( "with current his speed will be x+3 mph \n" ); document.write( "with current he paddled for (x+3) * 1\r \n" ); document.write( "\n" ); document.write( "against current his speed will be x-3 mph \n" ); document.write( "against current he paddled f or (x-3)*2\r \n" ); document.write( "\n" ); document.write( "Rick with current for 1.5 hrs. \n" ); document.write( " let Rick's speed in still water be y \n" ); document.write( "with current his speed will be y+3 mph \n" ); document.write( "with current he paddled for (y+3) * 1.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rick paddled against current for 2.5 hrs. \r \n" ); document.write( "\n" ); document.write( "against current his speed will be y-3 mph \n" ); document.write( "against current he paddled f or (y-3)*2.5\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If they paddled a total of 9.5 miles against the current \n" ); document.write( "(x-3)*2 +(y-3)*2.5 = 9.5 \n" ); document.write( "2x-6 +2.5y -7.5 =9.5 \n" ); document.write( "2x+2.5y = 23...........................(1)\r \n" ); document.write( "\n" ); document.write( " and 20.5 miles with the current\r \n" ); document.write( "\n" ); document.write( "(x+3) * 1+ (y+3) * 1.5=20.5\r \n" ); document.write( "\n" ); document.write( "x+3 +1.5y +4.5 =20.5\r \n" ); document.write( "\n" ); document.write( "x+1.5y=13.......................(2)\r \n" ); document.write( "\n" ); document.write( "2.00 x + 2.50 y = 23.00 .............1 \n" ); document.write( " \n" ); document.write( "1.00 x + 1.50 y = 13.00 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -1.50 \n" ); document.write( "Multiply (2) by 2.50 \n" ); document.write( "-3.00 x -3.75 y = -34.50 \n" ); document.write( "2.50 x + 3.75 y = 32.50 \n" ); document.write( "Add the two equations \n" ); document.write( "-0.50 x = -2.00 \n" ); document.write( "/ -0.50 \n" ); document.write( "x = 4.00 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "2.00 x + 2.50 y = 23.00 \n" ); document.write( "8.00 + 2.50 y = 23.00 \n" ); document.write( " 2.50 y = 23.00 -8.00 \n" ); document.write( " 2.50 y = 15.00 \n" ); document.write( " y = 6.00 \n" ); document.write( "x= 4.00 mph Bob's speed \n" ); document.write( "y= 6.00 mph Rick's speed \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |