document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88936>Question 88936</A>: <I><SPAN STYLE=\"word-break: break-all;\"> These are on exponentials with logs; in case stan happens to see this, thanks alot for your help- I had to use my moms' last paycheck (she had to leave work to have surgery done on her anuerysms) to pay $400 for this class to make sure I have this Algebra II credit to graduate this upcoming year. You taking out time to do those 5 little problems were a BIG help and may god bless you.\r<BR>\n" );
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document.write( "2^x = 30\r<BR>\n" );
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document.write( "5^x - 1 = 3^x\r<BR>\n" );
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document.write( "3.5^3x + 1 = 65.4\r<BR>\n" );
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document.write( "16^x - 4 = 3^3 - x\r<BR>\n" );
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document.write( "7^x - 2 = 5^x<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64640 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2^x = 30 <BR>\n" );
document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "x(log2) = log30<BR>\n" );
document.write( "x = [log30]/[log2]<BR>\n" );
document.write( "x = 4.90689..\r<BR>\n" );
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document.write( "---------------------\r<BR>\n" );
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document.write( "5^(x - 1) = 3^x <BR>\n" );
document.write( "Take the log of both sides<BR>\n" );
document.write( "(x-1)log5 = xlog3<BR>\n" );
document.write( "xlog5 -xlo3 = log5<BR>\n" );
document.write( "x(log5 - log3) = log5<BR>\n" );
document.write( "x(0.2218487..) = 0.6987000...<BR>\n" );
document.write( "x = 5.15066...<BR>\n" );
document.write( "---------------\r<BR>\n" );
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document.write( "3.5^(3x + 1) = 65.4 <BR>\n" );
document.write( "Take the log of both sides:<BR>\n" );
document.write( "(3x+1)log3.5 = log65.4<BR>\n" );
document.write( "(3log3.5)x = log65.4<BR>\n" );
document.write( "x = 0.329266....<BR>\n" );
document.write( "-----------\r<BR>\n" );
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document.write( "16^(x - 4) = 3^(3 - x )<BR>\n" );
document.write( "Take the log of both sides<BR>\n" );
document.write( "(x-4)log16 = (3-x)log3<BR>\n" );
document.write( "Can you take it from here?<BR>\n" );
document.write( "--------\r<BR>\n" );
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document.write( "7^(x - 2) = 5^x<BR>\n" );
document.write( "Take the log of both sides<BR>\n" );
document.write( "Can you take it from here?<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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