document.write( "Question 1031682: (1/x+1) + (1/x+2) = 1\r
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Algebra.Com's Answer #646367 by rothauserc(4718)\"\" \"About 
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(1/(x+1)) + (1/(x+2)) = 1
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\n" ); document.write( "the common denominator is (x+1)*(x+2)
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\n" ); document.write( "multiply both sides of the = by the common denominator
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\n" ); document.write( "(x+2) + (x+1) = x^2+3x+2
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\n" ); document.write( "x^2 +x -1 = 0
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\n" ); document.write( "x^2 +x = 1
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\n" ); document.write( "complete the square
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\n" ); document.write( "x^2 +x + (1/4) = 1 + (1/4)
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\n" ); document.write( "(x+(1/2))^2 = 5/4
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\n" ); document.write( "take square root of both sides
\n" ); document.write( "x+(1/2) = square root(5)/2
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\n" ); document.write( "x = square root(5)/2 - (1/2) = 0.618033989
\n" ); document.write( "x = -square root(5)/2 - (1/2) = −1.618033989
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\n" ); document.write( "check the work by substituting for x in given equation
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