document.write( "Question 1031670: calculate the area under the curve y=f(x)= x^2 ln(x^3) from x=0 to x=1 \n" ); document.write( "
Algebra.Com's Answer #646356 by Alan3354(69443)\"\" \"About 
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calculate the area under the curve y=f(x)= x^2 ln(x^3) from x=0 to x=1
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\n" ); document.write( "f(x) = 3x^2*ln(x)
\n" ); document.write( "INT(x) = 3*(x^3*ln(x)/3 - x^3/9) --- ignore the constant of integration
\n" ); document.write( "INT(1) = 3*1*0/3 - 3*1/9 = -1/3
\n" ); document.write( "INT(0) = 0
\n" ); document.write( "--> area = 1/3 sq unit, below the x-axis.
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