document.write( "Question 88929: seven years ago,mary was 6times as old as cora.in one year,she will be only twice as old as cora.find their present ages \n" ); document.write( "
Algebra.Com's Answer #64634 by stanbon(75887)\"\" \"About 
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seven years ago,mary was 6 times as old as cora.in one year,she will be only twice as old as cora.find their present ages
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\n" ); document.write( "7 years ago DATA:
\n" ); document.write( "Cora's age = x ; Mary's age = 6x
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\n" ); document.write( "NOW DATA:
\n" ); document.write( "Cora's age = x+7 ; Mary's age = 6x+7
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\n" ); document.write( "One year from now DATA:
\n" ); document.write( "Cora's age = x+8 ; Mary's age = 6x+8
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\n" ); document.write( "EQUATION: (based on one year from now DATA)
\n" ); document.write( "6x+8 = 2(x+8)
\n" ); document.write( "6x+8 = 2x+16
\n" ); document.write( "4x = 8
\n" ); document.write( "x = 2
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\n" ); document.write( "x+7 = 9 yrs old (Cora's age NOW)
\n" ); document.write( "6x+7 = 19 yrs old (Mary's age NOW)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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