document.write( "Question 1031630: Bears have a mean height of 2.4 m and a standard deviation of 0.24 m. If there are 500 bears in Canada, how many of these would be expected to be less than 2.6 m in height? Give you answer as a whole number \n" ); document.write( "
Algebra.Com's Answer #646320 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "\r\n" );
document.write( "\"z=%28x-mu%29%2Fsigma\"\r\n" );
document.write( "\r\n" );
document.write( "\"z=%282.6-2.4%29%2F0.24\"\r\n" );
document.write( "\r\n" );
document.write( "\"z=0.8333\"\r\n" );
document.write( "\r\n" );
document.write( "From table, the best we can read is  0.83\r\n" );
document.write( "\r\n" );
document.write( "Some tables we read 0.7673 directly and some\r\n" );
document.write( "tables read 0.2673 and we have to add 0.5\r\n" );
document.write( "and get 0.7673, or on a more accurate TI \r\n" );
document.write( "calculator we can read 0.7976716754.\r\n" );
document.write( "\r\n" );
document.write( "We multiply by 500.  So if we use the table, \r\n" );
document.write( "we get 384 bears and if we use a TI calculator\r\n" );
document.write( "we get 399 bears.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );