document.write( "Question 1031497: the number of numbers lying between 10 and 1000 can be formed with the digits 2,3,4,0,8,9 is
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document.write( "a)124
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document.write( "b)120
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document.write( "c)125(correct)
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document.write( "d)none of these \n" );
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Algebra.Com's Answer #646210 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Case 1: two digit numbers:\r\n" ); document.write( "\r\n" ); document.write( "Choose the first digit 5 ways (can't choose 0)\r\n" ); document.write( "Choose the second digit 5 ways (can choose 0)\r\n" ); document.write( "\r\n" ); document.write( "That's 5*5 = 25 two digit numbers.\r\n" ); document.write( "\r\n" ); document.write( "Case 2: three digit numbers\r\n" ); document.write( "\r\n" ); document.write( "Choose the first digit 5 ways (can't choose 0)\r\n" ); document.write( "Choose the second digit 5 ways (can choose 0)\r\n" ); document.write( "Choose the third digit 4 ways.\r\n" ); document.write( "\r\n" ); document.write( "That's 5*5*4 = 100 three-digit numbers.\r\n" ); document.write( "\r\n" ); document.write( "Grand total: 25+100 = 125\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |