document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031486>Question 1031486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a solution of 72% fertilizer is to be mixed with a 26% fertilizer to form 230 liters of a 53% solution. How many liters of the 72% solution must be used </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646192 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a solution of 72% fertilizer is to be mixed with a 26% fertilizer to form 230 liters of a 53% solution. How many liters of the 72% solution must be used <BR>\n" );
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document.write( "Quantity:: s + t = 230 liters<BR>\n" );
document.write( "Fertilizer: 0.72s + 0.26t = 0.53*230<BR>\n" );
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document.write( "Modify for elimination::<BR>\n" );
document.write( "26s + 26t = 26*230<BR>\n" );
document.write( "72s + 26t = 53*230<BR>\n" );
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document.write( "Subtract and solve for \"s\"::<BR>\n" );
document.write( "46s = 27*230<BR>\n" );
document.write( "s = 135 liters (amt. of 72% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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