document.write( "Question 88818: \n" ); document.write( "
Algebra.Com's Answer #64619 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " find the value of a[n] if: n=2, a[1] and a[n]=3a[n-1]+1\r \n" ); document.write( "\n" ); document.write( " a(n) = 3a(n-1)+1 \n" ); document.write( " a(1) = 3a(1-1)+1 = 3a*0+1 = 0+1 = 1\r \n" ); document.write( "\n" ); document.write( " a(2) = 3a(2-1)+1 = 3a(1)+1 = 3a+1 \n" ); document.write( " |