document.write( "Question 1031498: How many liters each of a 35% acid solution and a 85% acid solution must be used to produce 50 liters of a 55% acid solution? (Round to two decimal places if necessary.) \n" ); document.write( "

Algebra.Com's Answer #646189 by ikleyn(52790) $\"\"$ $\"About$

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\n" ); document.write( "How many liters each of a 35% acid solution and a 85% acid solution must be used to produce 50 liters of a 55% acid solution?
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document.write( "Let x be the required volume of a 35% acid solution, in liters.\r\n" );
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document.write( "Then the volume of a 85% acid solution is (50-x)\r\n" );
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document.write( "The equation for the pure acid volume is \r\n" );
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document.write( "0.35x + 0.85*(50-x) = 0.55*50.\r\n" );
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document.write( "Simplify and solve:\r\n" );
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document.write( "0.35x + 42.5 - 0.85x = 27.5,\r\n" );
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document.write( "-0.5x = 27.5 - 42.5,\r\n" );
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document.write( "-0.5x = -15,\r\n" );
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document.write( "x =  = 30.\r\n" );
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document.write( "Answer. 30 liters of the 35% acid solution and (50-30) = 20 liters of the 85% acid solution is needed.\r\n" );
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