document.write( "Question 1031478: I am to simplify this expression (2x-3y)^2 / (3y-2x)^2\r
\n" ); document.write( "\n" ); document.write( "My work is...
\n" ); document.write( "(2x-3y)^2 / (3y-2x)^2
\n" ); document.write( "=(2x-3y)^2 / [-(2x-3y)]^2
\n" ); document.write( "=(2x-3y)^2 / (2x-3y)^2
\n" ); document.write( "=-1
\n" ); document.write( "What am I doing wrong? My teacher states my answer is incorrect. Please tell me what I am missing. Thank you.
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Algebra.Com's Answer #646152 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
=(2x-3y)^2 / (3y-2x)^2
\n" ); document.write( "=(2x-3y)^2 / [-(2x-3y)]^2
\n" ); document.write( "=(2x-3y)^2 / (2x-3y)^2 <----- How do you go from this step to the next step?\r
\n" ); document.write( "\n" ); document.write( "Since
\n" ); document.write( "Z/Z=1
\n" ); document.write( "Why does your final step equal -1?
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