document.write( "Question 1031342: n 1974 a mother is 6 times as old as her daughter. The mother turned 50 in the year 2000. In what year was the mother double her daughter’s age? \n" ); document.write( "

Algebra.Com's Answer #646083 by ikleyn(52832) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "In 1974 a mother is 6 times as old as her daughter. The mother turned 50 in the year 2000. In what year was the mother double her daughter’s age?
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "Since the mother was 50 years old in 2000, she was 50 - (2000-1974) = 50 - 26 = 24 years old in 1974.\r\n" );
document.write( "\r\n" );
document.write( "Hence, the daughter was  = 4 years old in 1974.\r\n" );
document.write( "\r\n" );
document.write( "In \"x\" years after 1974, the daughter will be 4+x years old, while the mother will be 24+x years old.\r\n" );
document.write( "\r\n" );
document.write( "We need to find \"x\" from the equation\r\n" );
document.write( "\r\n" );
document.write( "2(4 + x) = 24+x.\r\n" );
document.write( "\r\n" );
document.write( "8 + 2x = 24 + x,\r\n" );
document.write( "\r\n" );
document.write( "x = 24 - 8 = 16.\r\n" );
document.write( "\r\n" );
document.write( "1974 + 16 = 1990.\r\n" );
document.write( "\r\n" );
document.write( "Answer.  In 1990 the mother doubles her daughter’s age.\r\n" );
document.write( "\r\n" );
document.write( "Check.  In 1990 mother's age is/was 24 + 16 = 40 years.\r\n" );
document.write( "        In 1990 the daughter's age is/was  4 + 16 = 20 years.   OK.\r\n" );
document.write( "

\n" ); document.write( " \n" ); document.write( "

\n" );