document.write( "Question 1031264: Jenny needs to find sin2x, and she knows that 0 < x < π. She also knows that sin2x and cosx are 7/25 and 24/25, but she doesn't know which is which.
\n" );
document.write( "a) why isn't it necessary for her to distinguish between the two?
\n" );
document.write( "b) Find the value of sin2x for both cases \n" );
document.write( "
Algebra.Com's Answer #646057 by richard1234(7193) You can put this solution on YOUR website! Do you mean sin 2x, or sin^2 x?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, if cos x = 24/25, then sin x = 7/25 (since 0 < x < pi, so sin x is positive, and using the fact that sin^2 x + cos^2 x = 1), and it is impossible for sin 2x or sin^2 x to also equal 7/25. Same thing if cos x = 7/25. \n" ); document.write( " |