document.write( "Question 1031304: How many 4 digit numbers can be formed out of the digits (3,4,5,6,7)which are greater than 5000 and no digit is repeated.the options are
\n" ); document.write( "a)72(correct)
\n" ); document.write( "b)27
\n" ); document.write( "c)70
\n" ); document.write( "d)none of these\r
\n" ); document.write( "\n" ); document.write( "I tried to solve it in the following way
\n" ); document.write( "if it is a 4 digit number greater than 5000 then the first number can be 5,6 or 7 so we have three choices
\n" ); document.write( "the second digit can be any of the above numbers(3,4,5,6,7)so we have 5 choices as no digit can be repeated we are left with 4 and 3 choices for the 3rd and 4th digit respectively
\n" ); document.write( "we can summarize it with the help of the fundamental principle of counting as
\n" ); document.write( "3*5*4*3=180
\n" ); document.write( "but this is wrong,
\n" ); document.write( "the correct answer is 72
\n" ); document.write( "please reply as soon as possible
\n" ); document.write( "thank you
\n" ); document.write( "yours sincerely
\n" ); document.write( "sukhdeep
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #646044 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "1.  Any of three numbers (5, 6, 7) in the first (from the left) position;\r\n" );
document.write( "2.  any of 4 remaining numbers in the second position;\r\n" );
document.write( "3.  any of 3 remaining numbers in the third  position;\r\n" );
document.write( "4.  any of 2 remaining numbers in the fourth position.\r\n" );
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document.write( "3*4*3*2 = 72.\r\n" );
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