document.write( "Question 1031230: Kelly has $5000 to deposit into two accounts. one account earn 4.5% simple interest, the other account earns 7.5% simple interest. After 1 year, the total interest earned in both accounts is $363. How much was invested in each account ?
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Algebra.Com's Answer #646016 by mananth(16946)\"\" \"About 
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\n" ); document.write( "Part I 4.50% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 7.50% per annum ------------ Amount invested = y =
\n" ); document.write( " 5000
\n" ); document.write( "Interest----- 363
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\n" ); document.write( "Part I 4.50% per annum ---x
\n" ); document.write( "Part II 7.50% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 5000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.50% x + 7.50% y= 363
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4.5 x + 7.5 y= 36300.00 --------2
\n" ); document.write( "Multiply (1) by -4.5
\n" ); document.write( "we get
\n" ); document.write( "-4.5 x -4.5 y= -22500.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 3 y= 13800
\n" ); document.write( "divide by 3
\n" ); document.write( " y = 4600
\n" ); document.write( "Part I 4.50% $ 400
\n" ); document.write( "Part II 7.50% $ 4600
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\n" ); document.write( "CHECK
\n" ); document.write( "400 --------- 4.50% ------- 18.00
\n" ); document.write( "4600 ------------- 7.50% ------- 345.00
\n" ); document.write( "Total -------------------- 363.00
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\n" ); document.write( "m.ananth@hotmail.ca
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