document.write( "Question 1031230: Kelly has $5000 to deposit into two accounts. one account earn 4.5% simple interest, the other account earns 7.5% simple interest. After 1 year, the total interest earned in both accounts is $363. How much was invested in each account ?
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Algebra.Com's Answer #646016 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Part I 4.50% per annum ------------- Amount invested =x \n" ); document.write( "Part II 7.50% per annum ------------ Amount invested = y = \n" ); document.write( " 5000 \n" ); document.write( "Interest----- 363 \n" ); document.write( " \n" ); document.write( "Part I 4.50% per annum ---x \n" ); document.write( "Part II 7.50% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 5000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "4.50% x + 7.50% y= 363 \n" ); document.write( "Multiply by 100 \n" ); document.write( "4.5 x + 7.5 y= 36300.00 --------2 \n" ); document.write( "Multiply (1) by -4.5 \n" ); document.write( "we get \n" ); document.write( "-4.5 x -4.5 y= -22500.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 3 y= 13800 \n" ); document.write( "divide by 3 \n" ); document.write( " y = 4600 \n" ); document.write( "Part I 4.50% $ 400 \n" ); document.write( "Part II 7.50% $ 4600 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "400 --------- 4.50% ------- 18.00 \n" ); document.write( "4600 ------------- 7.50% ------- 345.00 \n" ); document.write( "Total -------------------- 363.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |