document.write( "Question 1031260: HCF of two numbers is 145 and their LCM is 2175 . if one number is 725 . find the other number .
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Algebra.Com's Answer #646014 by Edwin McCravy(20056) $\"\"$ $\"About$

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document.write( "Get the prime factorizations of all three numbers\r\n" );
document.write( "HCF = 145 = 5*29\r\n" );
document.write( "LCM = 2175 = 3*5*5*29\r\n" );
document.write( "one number = 725 = 5*5*29\r\n" );
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document.write( "The other number must contain a factor of 3 for 2175 to be the LCM.\r\n" );
document.write( "The other number must contain factors 5 and 29 for 145 to be the HCF.\r\n" );
document.write( "So the other number is 3*5*29 = 435\r\n" );
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document.write( "Edwin

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