document.write( "Question 1031179: Write the given expression in terms of x and y only.
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Algebra.Com's Answer #645996 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"tan%28sin%5E%28-1%29%282%2F3%29+-+cos%5E%28-1%29%281%2F3%29%29\".\r\n" );
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document.write( "When solving problems like this, half of the success is to reformulate it reasonably.\r\n" );
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document.write( "So I will do it now.  We need to calculate  \"tan%28alpha+-+beta%29\",  where  \"alpha\" = \"arcsin%282%2F3%29\"  and  \"beta\" = \"arccos%281%2F3%29\".\r\n" );
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document.write( "So we have the angle  \"alpha\"  in Q1  with \"sin%28alpha%29\" = \"2%2F3\",  and the angle  \"beta\"  in Q1  with \"cos%28beta%29\" = \"1%2F3\".\r\n" );
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document.write( "Since \"tan%28alpha+-+beta%29\" = \"sin%28alpha-beta%29%2Fcos%28alpha-beta%29\", the plan is to calculate \"sin%28alpha-beta%29\" and \"cos%28alpha-beta%29\".  //Making a good plan is the second half of the success. \r\n" );
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document.write( "To calculate  \"sin%28alpha-beta%29\"  and  \"cos%28alpha-beta%29\",  we will use well known formulas of Trigonometry\r\n" );
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document.write( "\"sin%28alpha-beta%29\" = \"sin%28alpha%29%2Acos%28beta%29+-+cos%28alpha%29%2Asin%28beta%29\"  and  \"cos%28alpha-beta%29\" = \"cos%28alpha%29%2Acos%28beta%29+%2B+sin%28alpha%29%2Asin%28beta%29\".    (1)\r\n" );
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document.write( "   (Regarding these formulas, see the lesson  Addition and subtraction formulas  in this site). \r\n" );
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document.write( "Looking into the formulas (1), you see that we need to know/to have the values  \"cos%28alpha%29\"  and  \"sin%28beta%29\"  \r\n" );
document.write( "in addition to the given values of  \"sin%28alpha%29\"  and  \"cos%28beta%29\".  It is easy.  \r\n" );
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document.write( "First, \"cos%28alpha%29\" = \"sqrt%281+-+sin%5E2%28alpha%29%29\" = \"sqrt%281+-+%282%2F3%29%5E2%29\" = \"sqrt%281-4%2F9%29\" = \"sqrt%285%29%2F3\". Second, \"sin%28beta%29\" = \"sqrt%281+-+cos%5E2%28beta%29%29\" = \"sqrt%281+-+%281%2F3%29%5E2%29\" = \"sqrt%281-1%2F9%29\" = \"sqrt%288%29%2F3\" = \"%282%2Asqrt%282%29%29%2F3\".\r\n" );
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document.write( "Notice that the signs at square roots are chosen \"+\" since the angles \"alpha\" and \"beta\" both lie in Q1.\r\n" );
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document.write( "Now you have everything to calculate \"sin%28alpha-beta%29\" and \"cos%28alpha-beta%29\" according to (1).  //Implementing the plan accurately is the third half of the success.\r\n" );
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document.write( "\"sin%28alpha-beta%29\" = \"%282%2F3%29%2A%281%2F3%29-%28sqrt%285%29%2F3%29%2A%28%282%2Asqrt%282%29%29%2F3%29\" = \"2%2F9+-+%282%2Asqrt%2810%29%29%2F9\" = \"%282-2%2Asqrt%2810%29%29%2F9\".   (by the way, it shows that \"alpha-beta\" lies in Q4).\r\n" );
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document.write( "\"cos%28alpha-beta%29\" = \"%28sqrt%285%29%2F3%29%2A%281%2F3%29+%2B+%282%2F3%29%2A%28%282%2Asqrt%282%29%29%2F3%29\" = \"%28sqrt%285%29%2B4%2Asqrt%282%29%29%2F9\". \r\n" );
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document.write( "And finally  \"tan%28alpha-beta%29\" = \"%282-2%2Asqrt%2810%29%29%2F%28sqrt%285%29%2B4%2Asqrt%282%29%29\".    (2)\r\n" );
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document.write( "If you rationalize the denominator in (2),  you will get the answer  \"tan%28alpha-beta%29\" = \"-%282%2A%28sqrt%285%29-sqrt%282%29%29%29%2F3\".\r\n" );
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document.write( "Answer.  \"-%282%2A%28sqrt%285%29-sqrt%282%29%29%29%2F3\".\r\n" );
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