document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031232>Question 1031232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There's a circular field. At the edge of the field is stake. Tied to the stake is a goat What is the formula to figure how long the needs to be to allow the goat the eat exactly half the area of the field? Griffox24@aol.com </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645982 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a semi-circle is pi * r^2 / 2<BR>\n" );
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document.write( "Suppose r is 4, then area of semicircle is 8pi<BR>\n" );
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document.write( "Let L be the length of rope tied to goat, then<BR>\n" );
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document.write( "piL^2 = 8pi<BR>\n" );
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document.write( "L^2 = 8<BR>\n" );
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document.write( "L = 2square root(2)<BR>\n" );
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document.write( "The ratio is 2square root(2) / 4 = 0.71<BR>\n" );
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document.write( "The length of rope is 0.71r, where r is the radius of the circular field\r<BR>\n" );
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