document.write( "Question 1031190: Two years ago Philip was three times as old as his son.
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document.write( "Two years hence, twice his age will be equal to five times
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document.write( "that of his son. Find their present ages. \n" );
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Algebra.Com's Answer #645932 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Two years ago Philip was three times as old as his son.\r\n" ); document.write( "Two years hence, twice his age will be equal to five times \r\n" ); document.write( "that of his son. Find their present ages.\r\n" ); document.write( "\r\n" ); document.write( "Let Philip's present age be P\r\n" ); document.write( "Let his son's present age be S\r\n" ); document.write( "\r\n" ); document.write( "Two years ago Philip was...\r\n" ); document.write( "\r\n" ); document.write( "Two years ago Philip was P-2\r\n" ); document.write( "Two years ago his son was S-2\r\n" ); document.write( "\r\n" ); document.write( "Two years ago Philip was three times as old as his son.\r\n" ); document.write( "\r\n" ); document.write( " P-2 = 3(S-2)\r\n" ); document.write( " P-2 = 3S-6\r\n" ); document.write( "P-3S = -4 \r\n" ); document.write( "\r\n" ); document.write( "Two years hence, \r\n" ); document.write( "\r\n" ); document.write( "Two years hence Philip will be P+2\r\n" ); document.write( "Two years hence his son will be will be S+2\r\n" ); document.write( "\r\n" ); document.write( "Two years hence, twice his age will be equal to five \r\n" ); document.write( "times that of his son. \r\n" ); document.write( "\r\n" ); document.write( "2(P+2) = 5(S+2)\r\n" ); document.write( " 2P+4 = 5S+10\r\n" ); document.write( " 2P-5S = 6 \r\n" ); document.write( "\r\n" ); document.write( "Solve the system either by substitution or elimination:\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |