document.write( "Question 1031190: Two years ago Philip was three times as old as his son.
\n" ); document.write( "Two years hence, twice his age will be equal to five times
\n" ); document.write( "that of his son. Find their present ages.
\n" ); document.write( "

Algebra.Com's Answer #645932 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "Two years ago Philip was three times as old as his son.\r\n" );
document.write( "Two years hence, twice his age will be equal to five times \r\n" );
document.write( "that of his son.  Find their present ages.\r\n" );
document.write( "\r\n" );
document.write( "Let Philip's present age be P\r\n" );
document.write( "Let his son's present age be S\r\n" );
document.write( "\r\n" );
document.write( "Two years ago Philip was...\r\n" );
document.write( "\r\n" );
document.write( "Two years ago Philip was P-2\r\n" );
document.write( "Two years ago his son was S-2\r\n" );
document.write( "\r\n" );
document.write( "Two years ago Philip was three times as old as his son.\r\n" );
document.write( "\r\n" );
document.write( " P-2 = 3(S-2)\r\n" );
document.write( " P-2 = 3S-6\r\n" );
document.write( "P-3S = -4 \r\n" );
document.write( "\r\n" );
document.write( "Two years hence, \r\n" );
document.write( "\r\n" );
document.write( "Two years hence Philip will be P+2\r\n" );
document.write( "Two years hence his son will be will be S+2\r\n" );
document.write( "\r\n" );
document.write( "Two years hence, twice his age will be equal to five \r\n" );
document.write( "times that of his son.  \r\n" );
document.write( "\r\n" );
document.write( "2(P+2) = 5(S+2)\r\n" );
document.write( "  2P+4 = 5S+10\r\n" );
document.write( " 2P-5S = 6  \r\n" );
document.write( "\r\n" );
document.write( "Solve the system either by substitution or elimination:\r\n" );
document.write( "\r\n" );
document.write( "\"system%28P-3S+=+-4%2C++2P-5S+=+6%29\"\r\n" );
document.write( "\r\n" );
document.write( "You finish.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );