document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031157>Question 1031157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If in 2=a and in 3=b, write the expression in (12) in terms of a and b.<BR>\n" );
document.write( "You are not being asked to approximate the value of the expression.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645926 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If ln 2=a and ln 3=b, write the expression ln (12) in terms of a and b.<BR>\n" );
document.write( "You are not being asked to approximate the value of the expression.<BR>\n" );
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document.write( "12 = 2^2*3<BR>\n" );
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document.write( "ln(12) = ln(2^2 * 3) = ln(2^2) + ln(3) = 2ln(2) + ln(3) = 2a + b<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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