document.write( "Question 88895: Can you please explain in detail for me...Thank You...\r
\n" ); document.write( "\n" ); document.write( "2/\"y%5E2-7y%2B12\" - 1/\"y%5E2-9\" = 4/\"y%5E2-y-12\"
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Algebra.Com's Answer #64592 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2/{y^2-7y+12} - 1/{y^2-9} = 4/{y^2-y-12}\r
\n" ); document.write( "\n" ); document.write( "Factor where you can to get:\r
\n" ); document.write( "\n" ); document.write( "[2/[(y-3)(y-4)] - 1/[(y-3)(y+3)] = 4/[(y-4)(x+3)]\r
\n" ); document.write( "\n" ); document.write( "Multiply thru by (y-3)(y-4)(y+3) to get:\r
\n" ); document.write( "\n" ); document.write( "2(y+3) - [y-4] = 4(y-3)
\n" ); document.write( "2y+6-y+4 = 4y-12
\n" ); document.write( "3y=22
\n" ); document.write( "y= 22/3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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