document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031180>Question 1031180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the expression in terms of sine only.<BR>\n" );
document.write( "-&#8730;3sin(x) + cos(x)<BR>\n" );
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document.write( "Write the expression in terms of sine only.<BR>\n" );
document.write( "3(sin(2x) &#8722; cos(2x))\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645917 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write the expression in terms of sine only.<BR>\n" );
document.write( "-&#8730;(3sin(x) + cos(x)) = -sqrt[3sin(x)+sqrt(1-sin^2(x)]\r<BR>\n" );
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document.write( "Write the expression in terms of sine only.<BR>\n" );
document.write( "3(sin(2x) &#8722; cos(2x)) <BR>\n" );
document.write( "= 3(2sin*cos - (cos^2-sin^2) <BR>\n" );
document.write( "= 3(2sin*sqrt(1-sin^2)-(1-2sin^2))<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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