document.write( "Question 88893: Find each product
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document.write( "1.(3x)(4x^3)(-x^5)
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document.write( "2.5x^3(4x^5-2x)
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document.write( "3. (5x-2y)^2
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document.write( "4. (5x+1)(3x^2-3x-2) \n" );
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Algebra.Com's Answer #64591 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! Find each product \n" ); document.write( "1.(3x)(4x^3)(-x^5) \n" ); document.write( "2.5x^3(4x^5-2x) \n" ); document.write( "3. (5x-2y)^2 \n" ); document.write( "4. (5x+1)(3x^2-3x-2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 1)(3x)(4x^3)(-x^5) \n" ); document.write( " =(12x^3+1)(-x^5) \n" ); document.write( " = 12x^4(-x^5) \n" ); document.write( " = -12x^4+5 \n" ); document.write( " = -12x^9\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 2)5x^3(4x^5-2x) \n" ); document.write( " = (5x^3)(4x^5)- (5x^3)(2x) \n" ); document.write( " = (20x^3+5)-(10x^3+1) \n" ); document.write( " = 20x^8-10x^4\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 3)(5x-2y)^2 \n" ); document.write( " = (5x)^2-2*5x*2y+(2y)^2 \n" ); document.write( " = 25x^2-20xy=4y^2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 4)(5x+1)(3x^2-3x-2) \n" ); document.write( " = 5x(3x^2-3x-2)+1(3x^2-3x-2) \n" ); document.write( " = 15x^3-15x^2-10x+3x^2-3x-2 \n" ); document.write( " = 15x^3-12x^2-13x-2 \n" ); document.write( " \n" ); document.write( " |