document.write( "Question 1030957: Hi\r
\n" ); document.write( "\n" ); document.write( "a chemical solution was made by mixing acid with water in the ratio of 1:4.the solution was then mixed with water in the ratio of 1:3.if 120ml of water was added to make the final solution how much acid was used.\r
\n" ); document.write( "\n" ); document.write( "thank you \n" ); document.write( "

Algebra.Com's Answer #645889 by KMST(5328) $\"\"$ $\"About$

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THE FIFTH GRADER SOLUTION:
\n" ); document.write( "To make the final solution, 3 parts of water were added to 1 part of the first mixture.
\n" ); document.write( "If those 3 parts were 120 mL of water, then 1 part was $\"120mL%2F3=40mL\"$ .
\n" ); document.write( "The first mixture had 1 part of acid in 5 parts of total mixture (1 part + 4 parts of the 1:4 mixture).
\n" ); document.write( "If those 5 parts were 40 mL, then the original 1 part of acid was
\n" ); document.write( " $\"40mL%2F5=highlight%288mL%29\"$ .
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\n" ); document.write( "MAKING IT LOOK LIKE ALGEBRA:
\n" ); document.write( " $\"x\"$ = volume of acid used, in mL.
\n" ); document.write( " $\"4x\"$ = volume of water (in mL) mixed with $\"x\"$ mL of acid.
\n" ); document.write( " $\"x%2B4x=5x\"$ = volume of 1:4 acid:water mixture, in mL.
\n" ); document.write( " $\"5x%2F120=1%2F3\"$ = ratio of volumes of first mixture to water added to make the final solution.
\n" ); document.write( " $\"5x%2F120=1%2F3\"$ --> $\"%285x%293=1%2A120\"$ --> $\"15x=120\"$ --> $\"x=120%2F15\"$ --> $\"highlight%28x=8%29\"$ \n" ); document.write( "

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