document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031145>Question 1031145</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dave and bill each start saving today. Dave saves 30 cents per day. Bill saves 1 cent on the first day, 2 cents on the second day, 3 cents on the third day and so on saving one more cent each day than on the day before. At the end of how many days will they have saved the same total amount? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645864 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645864\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number of days be x when they have saved the same amount\r<BR>\n" );
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document.write( "Dave saves 30x after x days\r<BR>\n" );
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document.write( "Bill saves 1 cent more everyday\r<BR>\n" );
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document.write( "1,2,3,4,......n\r<BR>\n" );
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document.write( "An Arithmetic sequence\r<BR>\n" );
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document.write( "Sx = x/2( 2+(x-1)1)\r<BR>\n" );
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document.write( "30x = x/2(2+(x-1))\r<BR>\n" );
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document.write( "60x =x(x+1)\r<BR>\n" );
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document.write( "x^2+x=60x\r<BR>\n" );
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document.write( "x+1=60<BR>\n" );
document.write( "x=59 days\r<BR>\n" );
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document.write( "After 59 days they will have saved the same\r<BR>\n" );
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document.write( "CHECK<BR>\n" );
document.write( "Dave => 30*59 = 1770\r<BR>\n" );
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document.write( "Bill => 59/2( 2+(59-1)1)\r<BR>\n" );
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document.write( "= 59/2(2+58)\r<BR>\n" );
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document.write( "= 59/2 * 60\r<BR>\n" );
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document.write( "= 59*60 =1770 \r<BR>\n" );
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document.write( " </SPAN>\n" );
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