document.write( "Question 88888: How many liters of an 11% alcohol solution should be mixed with 60 liters of a 5% alcohol solution to obtain a mixture that is 7% alcohol? \n" ); document.write( "
Algebra.Com's Answer #64586 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many liters of an 11% alcohol solution should be mixed with 60 liters of a 5% alcohol solution to obtain a mixture that is 7% alcohol? \n" ); document.write( "--------- \n" ); document.write( "Amt of 5% solution = 60 L ; amt of active ingredient = 0.05*60 = 3 L \n" ); document.write( "------- \n" ); document.write( "Amt of 11% solution = x L ; amt of active ingredient = 0.11x L \n" ); document.write( "--------------- \n" ); document.write( "Amt of 7% mixture = (60+x) L ; Amt of active ingre = 0.07(60+x) = 4.2+0.07x L \n" ); document.write( "=================== \n" ); document.write( "EQUATION: \n" ); document.write( "active + active = active \n" ); document.write( "3 + 0.11x = 4.2+0.07x \n" ); document.write( "0.04x = 1.2 \n" ); document.write( "x = 30 liters (amt of 11% solution that must be mixed) \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |