document.write( "Question 88888: How many liters of an 11% alcohol solution should be mixed with 60 liters of a 5% alcohol solution to obtain a mixture that is 7% alcohol? \n" ); document.write( "
Algebra.Com's Answer #64586 by stanbon(75887)\"\" \"About 
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How many liters of an 11% alcohol solution should be mixed with 60 liters of a 5% alcohol solution to obtain a mixture that is 7% alcohol?
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\n" ); document.write( "Amt of 5% solution = 60 L ; amt of active ingredient = 0.05*60 = 3 L
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\n" ); document.write( "Amt of 11% solution = x L ; amt of active ingredient = 0.11x L
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\n" ); document.write( "Amt of 7% mixture = (60+x) L ; Amt of active ingre = 0.07(60+x) = 4.2+0.07x L
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\n" ); document.write( "EQUATION:
\n" ); document.write( "active + active = active
\n" ); document.write( "3 + 0.11x = 4.2+0.07x
\n" ); document.write( "0.04x = 1.2
\n" ); document.write( "x = 30 liters (amt of 11% solution that must be mixed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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