document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88885>Question 88885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with the following problems. All of these problems ar inside of the curly brackets.. example {     } <BR>\n" );
document.write( "Solve by any convenient method : <BR>\n" );
document.write( "4x + 12y = 24<BR>\n" );
document.write( "2x + 6y = 12  \r<BR>\n" );
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document.write( "Solve by any convenient method : <BR>\n" );
document.write( "8x + 4y =7<BR>\n" );
document.write( "x = 2-2y\r<BR>\n" );
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document.write( "Solve by Elimination : <BR>\n" );
document.write( "2x -3y =-1<BR>\n" );
document.write( "3x + y +15\r<BR>\n" );
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document.write( "Solve by Substitution : \r<BR>\n" );
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document.write( "3x + 8y = 7<BR>\n" );
document.write( "x- 4y =9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64583 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   Solve by any convenient method : <BR>\n" );
document.write( "4x + 12y = 24                         1)4x+12y = 24 ..........eq'n(1)<BR>\n" );
document.write( "2x + 6y = 12                             2x+6y = 12...........eq'n(2) <BR>\n" );
document.write( "                                         divide eq'n (1) by 4 andeq'n (2) by 2<BR>\n" );
document.write( "                                        we get x+3y = 6    and x+3y =6<BR>\n" );
document.write( "                           there is no solution for this set of eq'ns as the <BR>\n" );
document.write( "       given eq'ns are inconsistent. (on solving the values of x & y are 0 which is meaningless)\r<BR>\n" );
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document.write( "Solve by any convenient method :   8x+4y = 7..........(1)<BR>\n" );
document.write( "8x + 4y =7<BR>\n" );
document.write( "x = 2-2y                           x+2y = 2............(2)\r<BR>\n" );
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document.write( "Solve by Elimination :             multiply  eq'n (2) by 2<BR>\n" );
document.write( "2x -3y =-1<BR>\n" );
document.write( "3x + y +15                         we get 2x+4y = 4.........eqe'n(3)\r<BR>\n" );
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document.write( "Solve by Substitution :            subtract eq'n(3) from eq'n(1)  we get <BR>\n" );
document.write( "3x + 8y = 7<BR>\n" );
document.write( "x- 4y =9                           6x = 3    or x = 3/6 = 1/2<BR>\n" );
document.write( "                                  substitute  for x  in eq'n(2)<BR>\n" );
document.write( "                                   2y = 2-x  = 2-1/2 = 4-1/2 = 3/2<BR>\n" );
document.write( "                                   solution  is x= 1/2  and y = 3/2\r<BR>\n" );
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document.write( "                               3)2x-3y = -1......eq'n(1)\r<BR>\n" );
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document.write( "                                 3x+y  = 15......eq'n(2)<BR>\n" );
document.write( "                                multiply eq'n(2)  by 3, we get 9x+3y = 45....(3)<BR>\n" );
document.write( "                              add eq''n(1) &eq'n(3) we get 11x = 44   or x = 4<BR>\n" );
document.write( "                               substitute for x in eq'n (2) we get 3(4)+y= 15\r<BR>\n" );
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document.write( "                                          12+y = 15  or y = 15-12 = 3\r<BR>\n" );
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document.write( "                          solution  is x = 4  and y = 3\r<BR>\n" );
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document.write( "                           4)3x+8y = 7.........eq'n(1)<BR>\n" );
document.write( "                             x-4y  = 9.........eq'n(2)<BR>\n" );
document.write( "                     from  eq'n(2) x = 9+4y.....eq'n(3)<BR>\n" );
document.write( "                            3(9+4y)+8y = 7     (by substituting for x)<BR>\n" );
document.write( "                            27+12y+8y  = 7<BR>\n" );
document.write( "                              20y   =  7-27 = -20 therefore y = -1\r<BR>\n" );
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document.write( "                             substituting for y in eq'n(2)  we get x = 9+4(-1)<BR>\n" );
document.write( "                                   x = 9-4 = 5\r<BR>\n" );
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document.write( "      therefore the solution  is x = 5  and y = -1\r<BR>\n" );
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document.write( "               </SPAN>\n" );
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