document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031103>Question 1031103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express the value as a trigonometric function of an angle in quadrant 1.<BR>\n" );
document.write( "cos1290 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645819 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Express the value as a trigonometric function of an angle in quadrant 1.<BR>\n" );
document.write( "cos1290 <BR>\n" );
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document.write( "I'm going to assume that is 1290 degrees.<BR>\n" );
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document.write( "1290/360 = 3.5833 = 3*360 + 0.5833*360<BR>\n" );
document.write( "Note: We can drop the 3*360 ; that leaves us with 0.5833*360 <BR>\n" );
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document.write( "0.5833*360 = 210 degrees<BR>\n" );
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document.write( "The reference angle for 210 degrees is 210-180 = 30 degrees<BR>\n" );
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document.write( "Note: 210 is in QIII where cos is negative.<BR>\n" );
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document.write( "Ans: cos(1290) = cos(210) = -cos(30)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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