document.write( "Question 1031099: On the moon, the acceleration due to gravity is constant 1.6 , i.e. a(t) = -1.6. If a ball is thrown into the air with an initial velocity of 2
at an initial height of 1 meter, find the height as a function of time, h(t).\r
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document.write( "All I know is that derivative of velocity is acceleration and the anti-derivative is the position. I don't know how to tie the elements together though. \n" );
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Algebra.Com's Answer #645813 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! On the moon, the acceleration due to gravity is constant 1.6 \n" ); document.write( "=================== \n" ); document.write( "h(t) = at^2/2 + vo*t + ho --- vo = start speed, ho = start height \n" ); document.write( "--- \n" ); document.write( "h(t) = -0.8t^2 + 2t + 1 \n" ); document.write( " \n" ); document.write( " |