document.write( "Question 1031099: On the moon, the acceleration due to gravity is constant 1.6 \"+m%2Fs%5E2+\", i.e. a(t) = -1.6. If a ball is thrown into the air with an initial velocity of 2\"+m%2Fs+\" at an initial height of 1 meter, find the height as a function of time, h(t).\r
\n" ); document.write( "\n" ); document.write( "All I know is that derivative of velocity is acceleration and the anti-derivative is the position. I don't know how to tie the elements together though.
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Algebra.Com's Answer #645813 by Alan3354(69443)\"\" \"About 
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On the moon, the acceleration due to gravity is constant 1.6 \"+m%2Fs%5E2+\", i.e. a(t) = -1.6. If a ball is thrown into the air with an initial velocity of 2\"+m%2Fs+\" at an initial height of 1 meter, find the height as a function of time, h(t).
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\n" ); document.write( "h(t) = at^2/2 + vo*t + ho --- vo = start speed, ho = start height
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\n" ); document.write( "h(t) = -0.8t^2 + 2t + 1
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