document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031036>Question 1031036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the terminal side of an angle  in standard position passes through the point (-1,5). Calculate the values of the six trigonometric functions for angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #645759 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=645759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> he terminal side of an angle in standard position passes through the point (-1,5). Calculate the values of the six trigonometric functions for angle. <BR>\n" );
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document.write( "Notice:: The terminal point is in QII where x is negative and y is positive.<BR>\n" );
document.write( "x = -1 ; y = 5 ; So, r = sqrt[1^2+5^2] = sqrt(26)<BR>\n" );
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document.write( "sin = y/r = 5/sqrt(26)<BR>\n" );
document.write( "cos = x/r = -1/sqrt(26)<BR>\n" );
document.write( "tan = y/x = -1/5<BR>\n" );
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document.write( "csc = 1/sin<BR>\n" );
document.write( "sec = 1/cos<BR>\n" );
document.write( "cot = 1/tan<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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