document.write( "Question 1031027: Solve this pair of simultaneous equations by substitution method:
\n" ); document.write( "y - 3x + 1 = 0
\n" ); document.write( "3x + 2y = 16
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Algebra.Com's Answer #645749 by LinnW(1048)\"\" \"About 
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y - 3x + 1 = 0
\n" ); document.write( "3x + 2y = 16
\n" ); document.write( "Add ( 3x - 1) to the top equation
\n" ); document.write( "y = 3x - 1
\n" ); document.write( "Substitute 3x - 1 for y in the second equation
\n" ); document.write( "3x + 2(3x - 1) = 16
\n" ); document.write( "3x + 6x - 2 = 16
\n" ); document.write( "9x - 2 = 16
\n" ); document.write( "add 2 to each side
\n" ); document.write( "9x = 18
\n" ); document.write( "divide each side by 9
\n" ); document.write( "x = 2
\n" ); document.write( "Substitute 2 for x in y = 3x - 1
\n" ); document.write( "y = 3(2) - 1
\n" ); document.write( "y = 6 - 1
\n" ); document.write( "y = 5
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