document.write( "Question 1031005: If John takes 4 times as long as it takes Jessica to mow the lawn, and it took them 10 hours to mow the lawn together, how long would it take John to mow the lawn alone? \n" ); document.write( "

Algebra.Com's Answer #645728 by fractalier(6550) $\"\"$ $\"About$

You can put this solution on YOUR website!
The general setup is like this
\n" ); document.write( " $\"t%2FA+%2B+t%2FB+=+1\"$
\n" ); document.write( "where A and B are how long it will take each to do the 1 job separately.
\n" ); document.write( "t is how long they work together.
\n" ); document.write( "Let A be how long it takes Jessica, then 4A is how long it takes John. We have
\n" ); document.write( " $\"10%2FA+%2B+10%2F4A+=+1\"$
\n" ); document.write( "Multiply by 4A and get
\n" ); document.write( " $\"40+%2B+10+=+4A\"$
\n" ); document.write( " $\"50+=+4A\"$
\n" ); document.write( "It would take John 50 hours by himself. (must be some lawn...) \n" ); document.write( "

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